1988 Tournament of the Americas
FIBA Americas Cup 1988 |
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3rd FIBA American Basketball Championship |
Tournament details |
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Host nation |
Uruguay |
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Dates |
22–31 May |
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Teams |
7 (from 41 federations) |
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Venues |
1 (in 1 host city) |
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Champions |
Brazil (2nd title) |
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The 1988 Tournament of the Americas, known now as the FIBA Americas Championship, was a basketball championship hosted by Uruguay from 22 to 31 May 1988. The games were played in Montevideo. This FIBA Americas Championship was to earn the three berths allocated to the Americas for the 1988 Summer Olympics in Seoul. The United States did not participate in the tournament, as the team had already been awarded a berth in the Olympics. Brazil defeated Puerto Rico in the final to win the tournament.[1] Canada beat Uruguay in the third place game to claim the final Olympic berth.
Qualification
Eight teams qualified during the qualification tournaments held in their respective zones in 1987; Canada qualified automatically since they are one of only two members of the North America zone. Panama and the Dominican Republic withdrew from the tournament. The teams formed a single group of seven teams.
Format
- The top four teams from the main group advance to the semifinals.
- The winners in the knockout semifinals advanced to the Final and were granted berths in the 1988 Summer Olympics tournament in Seoul. The losers figure in a third-place playoff where the winner was given the third and final place in the Olympics.
Preliminary round
| Qualified for the semifinals |
Knockout stage
Awards
1988 Tournament of the Americas Winners |
Brazil Second title |
Final standings
References
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