1989 Big Sky Conference Men's Basketball Tournament

1989 Big Sky Conference Men's Basketball Tournament
Classification Division I
Teams 6
Site BSU Pavilion
Boise, ID
Champions Idaho (3rd title)
Winning coach Kermit Davis (1st title)
MVP Riley Smith (Idaho)
Big Sky Conference Men's Basketball Tournaments
«1988  1990»

The 1989 Big Sky Conference Men's Basketball Tournament was held March 9–11 at the BSU Pavilion at Boise State University in Boise, Idaho.[1]

Second-seeded Idaho defeated the defending champions, top-seeded Boise State, in the championship game, 59–52, to take home their third Big Sky men's basketball tournament.

The Vandals, in turn, received an automatic bid to the 1989 NCAA Tournament. No other Big Sky members were invited to the tournament.

Format

No new teams were added to the Big Sky prior to the 1988–89 season, leaving total membership at nine.

Nonetheless, the tournament field was decreased from eight to six. With teams ranked based on regular season conference records, only the top six teams were invited to the tournament. The two top seeds were given byes into the semifinals while the third- through sixth-seeded teams were placed and paired into the preliminary quarterfinal round.

Bracket

  Quarterfinals
Thursday, March 9
Semifinals
Friday, March 10
Championship
Saturday, March 11
                           
        
  1  Boise State 71  
    5  Weber State 60  
5  Weber State 69
  4  Nevada 61  
    1  Boise State 52
  2  Idaho 59
  3  Montana 87  
6  Montana State 84  
3  Montana 56
    2  Idaho 77  
      

References

  1. "1988-89 Big Sky Conference Season Summary". sports-reference.com. Sports Reference LLC. 2016. Retrieved May 2, 2016.
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