Honkala Island
  Honkala Island Location in Antarctica | |
| Geography | |
|---|---|
| Location | Antarctica |
| Coordinates | 66°14′S 110°37′E / 66.233°S 110.617°ECoordinates: 66°14′S 110°37′E / 66.233°S 110.617°E |
| Length | 1.4 km (0.87 mi) |
| Administration | |
|
None | |
| Demographics | |
| Population | Uninhabited |
| Additional information | |
| Administered under the Antarctic Treaty System | |
Honkala Island is a rocky island, 1.4 kilometres (0.75 nmi) long, at the southeast side of Burnett Island, in the Swain Islands of Antarctica. It was first mapped from air photos taken by U.S. Navy Operation Highjump, 1946–47, and observed by Wilkes Station personnel who conducted a 1957 survey of the Swain Islands under Carl R. Eklund. It was named by Eklund for Rudolf A. Honkala, chief meteorologist with the United States International Geophysical Year wintering party of 1957 at Wilkes Station.[1]
See also
References
- ↑ "Honkala Island". Geographic Names Information System. United States Geological Survey. Retrieved 2012-06-24.
This article incorporates public domain material from the United States Geological Survey document "Honkala Island" (content from the Geographic Names Information System).
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