Unitary operator

For unitarity in physics, see Unitarity (physics).

In functional analysis, a branch of mathematics, a unitary operator (not to be confused with a unity operator) is defined as follows:

Definition 1. A unitary operator is a bounded linear operator $U : H \to H$ on a Hilbert space $H$ that satisfies $U * U = UU * = I$ , where $U *$ is the adjoint of $U$ , and $I : H \to H$ is the identity operator.

The weaker condition $U * U = I$ defines an isometry. The other condition, $UU * = I$ , defines a coisometry. Thus a unitary operator is a bounded linear operator which is both an isometry and a coisometry.^[1]

An equivalent definition is the following:

Definition 2. A unitary operator is a bounded linear operator $U : H \to H$ on a Hilbert space $H$ for which the following hold:

$U$ is surjective, and
$U$ preserves the inner product of the Hilbert space, $H$ . In other words, for all vectors $x$ and $y$ in $H$ we have:

\langle Ux, Uy \rangle_H = \langle x, y \rangle_H.

The following, seemingly weaker, definition is also equivalent:

Definition 3. A unitary operator is a bounded linear operator $U : H \to H$ on a Hilbert space $H$ for which the following hold:

the range of $U$ is dense in $H$ , and
$U$ preserves the inner product of the Hilbert space, $H$ . In other words, for all vectors $x$ and $y$ in $H$ we have:

\langle Ux, Uy \rangle_H = \langle x, y \rangle_H.

To see that Definitions 1 & 3 are equivalent, notice that $U$ preserving the inner product implies $U$ is an isometry (thus, a bounded linear operator). The fact that $U$ has dense range ensures it has a bounded inverse $U -1$ . It is clear that $U -1 = U *$ .

Thus, unitary operators are just automorphisms of Hilbert spaces, i.e., they preserve the structure (in this case, the linear space structure, the inner product, and hence the topology) of the space on which they act. The group of all unitary operators from a given Hilbert space $H$ to itself is sometimes referred to as the Hilbert group of $H$ , denoted $Hilb(H)$ .

A unitary element is a generalization of a unitary operator. In a unital *-algebra, an element $U$ of the algebra is called a unitary element if $U * U = UU * = I$ , where $I$ is the identity element.^[2]^:55

Examples

The identity function is trivially a unitary operator.
Rotations in $R 2$ are the simplest nontrivial example of unitary operators. Rotations do not change the length of a vector or the angle between two vectors. This example can be expanded to $R 3$ .
On the vector space $C$ of complex numbers, multiplication by a number of absolute value $1$ , that is, a number of the form $e iθ$ for $θ \in R$ , is a unitary operator. $θ$ is referred to as a phase, and this multiplication is referred to as multiplication by a phase. Notice that the value of $θ$ modulo $2 π$ does not affect the result of the multiplication, and so the independent unitary operators on $C$ are parametrized by a circle. The corresponding group, which, as a set, is the circle, is called $U(1)$ .
More generally, unitary matrices are precisely the unitary operators on finite-dimensional Hilbert spaces, so the notion of a unitary operator is a generalization of the notion of a unitary matrix. Orthogonal matrices are the special case of unitary matrices in which all entries are real. They are the unitary operators on $R n$ .
The bilateral shift on the sequence space $ℓ 2$ indexed by the integers is unitary. In general, any operator in a Hilbert space which acts by shuffling around an orthonormal basis is unitary. In the finite dimensional case, such operators are the permutation matrices.
The unilateral shift (right shift) is an isometry; its conjugate (left shift) is a coisometry.
The Fourier operator is a unitary operator, i.e. the operator which performs the Fourier transform (with proper normalization). This follows from Parseval's theorem.
Unitary operators are used in unitary representations.

Linearity

The linearity requirement in the definition of a unitary operator can be dropped without changing the meaning because it can be derived from linearity and positive-definiteness of the scalar product:

\begin{align} \| \lambda U(x) -U(\lambda x) \|^2 &= \langle \lambda U(x) -U(\lambda x), \lambda U(x)-U(\lambda x) \rangle \\ &= \| \lambda U(x) \|^2 + \| U(\lambda x) \|^2 - \langle U(\lambda x), \lambda U(x) \rangle - \langle \lambda U(x), U(\lambda x) \rangle \\ &= |\lambda|^2 \| U(x)\|^2 + \| U(\lambda x) \|^2 - \overline{\lambda} \langle U(\lambda x), U(x) \rangle - \lambda \langle U(x), U(\lambda x) \rangle \\ &= |\lambda|^2 \| x \|^2 + \| \lambda x \|^2 - \overline{\lambda} \langle \lambda x, x \rangle - \lambda \langle x, \lambda x \rangle \\ &= 0 \end{align}

Analogously you obtain

\| U(x+y)-(Ux+Uy)\| = 0.

Properties

The spectrum of a unitary operator $U$ lies on the unit circle. That is, for any complex number $λ$ in the spectrum, one has $| λ | = 1$ . This can be seen as a consequence of the spectral theorem for normal operators. By the theorem, $U$ is unitarily equivalent to multiplication by a Borel-measurable $f$ on $L 2 (μ)$ , for some finite measure space $(X, μ)$ . Now $UU * = I$ implies $| f (x)| 2 = 1$ , $μ$ -a.e. This shows that the essential range of $f$ , therefore the spectrum of $U$ , lies on the unit circle.
A linear map is unitary iff it is surjective and isometric. (Use Polarization identity to show the only if part.)

Footnotes

↑ (Halmos 1982, Sect. 127, page 69)
↑ Doran, Robert S.; Victor A. Belfi (1986). Characterizations of C*-Algebras: The Gelfand-Naimark Theorems. New York: Marcel Dekker. ISBN 0-8247-7569-4.

References

Lang, Serge (1972). Differential manifolds. Reading, Mass.–London–Don Mills, Ont.: Addison-Wesley Publishing Co., Inc.
Halmos, Paul (1982). A Hilbert space problem book. Springer.

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