Łopuchowo, Sejny County
For other places with the same name, see Łopuchowo.
| Łopuchowo | |
|---|---|
| Village | |
  Łopuchowo | |
| Coordinates: 54°6′N 23°18′E / 54.100°N 23.300°E | |
| Country |
 Poland |
| Voivodeship | Podlaskie |
| County | Sejny |
| Gmina | Krasnopol |
Łopuchowo [wɔpuˈxɔvɔ], is a village in the administrative district of Gmina Krasnopol, within Sejny County, Podlaskie Voivodeship, in north-eastern Poland.[1] It lies approximately 7 kilometres (4 mi) east of Krasnopol, 5 km (3 mi) south-west of Sejny, and 110 km (68 mi) north of the regional capital Białystok.
References
Coordinates: 54°06′00″N 23°18′00″E / 54.1000°N 23.3000°E
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