1905 Paris–Roubaix
Race details | |||
---|---|---|---|
Date | 23 April | ||
Distance | 268 km (166.5 mi) | ||
Winning time | 8h 4' 15" | ||
Results | |||
Winner | Louis Trousselier (FRA) | ||
Second | René Pottier (FRA) | ||
Third | Henri Cornet (FRA) | ||
The 1905 Paris–Roubaix was the tenth edition of the Paris–Roubaix, a classic one-day cycle race in France. The single day event was held on 23 April 1905 and stretched 268 km (167 mi) from Paris to its end in a velodrome in Roubaix.[1] The winner was Louis Trousselier from France.[2]
Results
Rank | Cyclist | Time |
---|---|---|
1 | Louis Trousselier (FRA) | 8h 4' 15″ |
2 | René Pottier (FRA) | +7' 00″ |
3 | Henri Cornet (FRA) | +16' 00″ |
4 | Hippolyte Aucouturier (FRA) | +23' 00″ |
5 | Edouard Wattelier (FRA) | +48' 00″ |
6 | Claude Chapperon (FRA) | +57' 00″ |
7 | Alois Catteau (BEL) | +1hr 6' 00″ |
8 | Paul Chauvet (FRA) | +1hr 12' 00″ |
9 | Lazare Brault (FRA) | +1hr 20' 00″ |
10 | Louis Colsaet (FRA) | +1hr 20' 01″ |
References
- ↑ "10th Paris – Roubaix, 1905". bikeraceinfo. Retrieved 27 February 2015.
- 1 2 "1905 » 10th Paris – Roubaix". ProCyclingStats. Retrieved 27 February 2015.
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