1905 Paris–Roubaix

1905 Paris–Roubaix
Race details
Date 23 April
Distance 268 km (166.5 mi)
Winning time 8h 4' 15"
Results
Winner  Louis Trousselier (FRA)
Second  René Pottier (FRA)
Third  Henri Cornet (FRA)

The 1905 Paris–Roubaix was the tenth edition of the Paris–Roubaix, a classic one-day cycle race in France. The single day event was held on 23 April 1905 and stretched 268 km (167 mi) from Paris to its end in a velodrome in Roubaix.[1] The winner was Louis Trousselier from France.[2]

Results

Final results (1–10)[2]
Rank Cyclist Time
1  Louis Trousselier (FRA) 8h 4' 15″
2  René Pottier (FRA) +7' 00″
3  Henri Cornet (FRA) +16' 00″
4  Hippolyte Aucouturier (FRA) +23' 00″
5  Edouard Wattelier (FRA) +48' 00″
6  Claude Chapperon (FRA) +57' 00″
7  Alois Catteau (BEL) +1hr 6' 00″
8  Paul Chauvet (FRA) +1hr 12' 00″
9  Lazare Brault (FRA) +1hr 20' 00″
10  Louis Colsaet (FRA) +1hr 20' 01″

References

  1. "10th Paris – Roubaix, 1905". bikeraceinfo. Retrieved 27 February 2015.
  2. 1 2 "1905 » 10th Paris – Roubaix". ProCyclingStats. Retrieved 27 February 2015.
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