Tępcz
| Tępcz | |
|---|---|
| Village | |
  Tępcz | |
| Coordinates: 54°30′23″N 18°2′22″E / 54.50639°N 18.03944°E | |
| Country |
 Poland |
| Voivodeship | Pomeranian |
| County | Wejherowo |
| Gmina | Luzino |
| Population | 319 |
Tępcz [tɛmpt͡ʂ] is a village in the administrative district of Gmina Luzino, within Wejherowo County, Pomeranian Voivodeship, in northern Poland.[1] It lies approximately 8 kilometres (5 mi) south-west of Luzino, 18 km (11 mi) south-west of Wejherowo, and 42 km (26 mi) west of the regional capital Gdańsk.
For details of the history of the region, see History of Pomerania.
The village has a population of 319.
References
| Seat |  | |
|---|---|---|
| Other villages | ||
Coordinates: 54°30′23″N 18°2′22″E / 54.50639°N 18.03944°E
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