United States presidential election in Delaware, 1828

United States presidential election in Delaware, 1828

October 31 – December 2, 1828

Nominee John Quincy Adams Andrew Jackson Party National Republican Democratic Home state Massachusetts Tennessee Running mate Richard Rush John C. Calhoun Electoral vote 3 0

The 1828 United States presidential election in Delaware took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

Delaware cast three electoral votes for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote.^[1]

Results

United States presidential election in Delaware, 1828[2]
Party		Candidate	Votes	Percentage	Electoral votes
	National Republican	John Quincy Adams	–	–	3
	Democratic	Andrew Jackson	–	–	0
Totals			–	–	3

References

1. "1828 Presidential General Election Results". U.S. Election Atlas. Retrieved 13 April 2013.
2. "Electoral Votes for President and Vice President 1821-1837". National Archives and Records Administration. Retrieved 2 March 2013.