United States presidential election in Pennsylvania, 1892

November 8, 1892

President before election

Benjamin Harrison
Republican

Elected President

Grover Cleveland
Democratic

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The 1892 United States presidential election in Pennsylvania took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose 32 representatives, or electors to the Electoral College, who voted for President and Vice President.

Pennsylvania voted for the Republican nominee, incumbent President Benjamin Harrison, over the Democratic nominee, former President Grover Cleveland, who was running for a second, non-consecutive term. Harrison won Pennsylvania by a margin of 6.36%.

Results

United States presidential election in Pennsylvania, 1892^[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	Benjamin Harrison (incumbent)	516,011	51.45%	32
	Democratic	Grover Cleveland	452,264	45.09%	0
	Prohibition	John Bidwell	25,123	2.50%	0
	People's	James Weaver	8,714	0.87%	0
	Socialist Labor	Simon Wing	898	0.09%	0
Totals			1,003,010	100.0%	32

State Results of the 1892 U.S. presidential election

Candidates	Grover Cleveland Benjamin Harrison James Weaver John Bidwell Full list

General articles	Election timeline Democratic primaries Republican primaries Republican Convention Democratic Convention Debates

Local results	Alabama Arkansas California Colorado Connecticut Delaware Florida Georgia Idaho Illinois Indiana Iowa Kansas Kentucky Louisiana Maine Maryland Massachusetts Michigan Minnesota Mississippi Missouri Montana Nebraska Nevada New Hampshire New Jersey New York North Carolina North Dakota Ohio Oregon Pennsylvania Rhode Island South Carolina South Dakota Tennessee Texas Vermont Virginia Washington West Virginia Wisconsin Wyoming

Other 1892 elections	House Senate Gubernatorial

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