Victorian state election, 1945
Victorian state election, 1945
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10 November 1945 (1945-11-10) |
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The 1945 Victorian state election was held in the Australian state of Victoria on Saturday 10 November 1945 to elect 65 members of the state's Legislative Assembly.
Results
Legislative Assembly
Victorian state election, 10 November 1945[1][2] Legislative Assembly
<< 1943 — 1947 >> |
Enrolled voters |
1,019,063 |
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|
Votes cast |
896,561 |
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Turnout |
87.98 |
+0.98 |
Informal votes |
18,689 |
|
Informal |
2.08 |
−0.51 |
Summary of votes by party |
Party |
Primary votes |
% |
Swing |
Seats |
Change |
|
Labor |
360,079 |
41.02 |
+4.89 |
31 |
+9 |
|
Country |
163,940 |
18.67 |
+5.64 |
18 |
±0 |
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Liberal |
180,046 |
20.51 |
−2.56 |
10 |
−3 |
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Independent |
92,097 |
10.49 |
−11.40 |
3 |
−2 |
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Ministerial Liberal |
29,276 |
3.33 |
+3.33 |
3 |
+3 |
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Independent Liberal |
27,351 |
3.12 |
+3.12 |
0 |
±0 |
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Communist |
25,083 |
2.86 |
−1.65 |
0 |
±0 |
Total |
877,872 |
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65 |
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Notes:
- Eleven seats were uncontested at this election, and were retained by the incumbent parties:
See also
References
- ↑ Election held on 10 November 1945, Australian Politics and Elections Database (University of Western Australia).
- ↑ Colin A Hughes, A Handbook of Australian Government and Politics 1890-1964, Canberra: Australian National University Press, 1968 (ISBN 0708102700).